(8x-x)^1+(4x+x)^1=90

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Solution for (8x-x)^1+(4x+x)^1=90 equation: 



(8x-x)^1+(4x+x)^1=90

We move all terms to the left:

(8x-x)^1+(4x+x)^1-(90)=0

We add all the numbers together, and all the variables

(+7x)^1+(+5x)^1-90=0

We move all terms containing x to the left, all other terms to the right

(+7x)^1+(+5x)^1=90

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